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7x-43x^2-43x+7=0
We add all the numbers together, and all the variables
-43x^2-36x+7=0
a = -43; b = -36; c = +7;
Δ = b2-4ac
Δ = -362-4·(-43)·7
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2500}=50$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-50}{2*-43}=\frac{-14}{-86} =7/43 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+50}{2*-43}=\frac{86}{-86} =-1 $
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